Hello Chet, thanks for your patch file. It is slightly broken, attached is the fixed version of your patch. BUT: it solves only half of the bug. Please check it yourself, here's the script: --- #!./bash -i set -m; cat echo Finished! while :; do jobs; sleep 2; done ---
Run this script, then do killall -STOP cat You'll start seeing the output of "jobs" every 2 seconds, and the cat is marked "Stopped". Then do killall -CONT cat Nothing changes, the cat is still listed as stopped. Then bash will run terminate_stopped_jobs() on it. :( Do you know how to fix also this? 29.12.2011 20:54, Chet Ramey wrote: > When you run bash with -i, interactive and interactive_shell are set > when initialize_job_control is called, so the correct initialization > happens. It's only later that job control gets turned off inappropriately. As a side note it would be nice to not flip the "interactive" value back and forth to make the code understanding easier.
--- shell.c.old 2009-11-19 18:05:54.000000000 +0300 +++ shell.c 2011-12-29 21:07:24.960908301 +0400 @@ -1618,7 +1618,7 @@ expand_aliases = posixly_correct; /* XXX - was 0 not posixly_correct */ no_line_editing = 1; #if defined (JOB_CONTROL) - set_job_control (0); + set_job_control (forced_interactive||jobs_m_flag); #endif /* JOB_CONTROL */ } --- flags.h.old 2009-01-04 22:32:29.000000000 +0300 +++ flags.h 2011-12-30 14:18:28.171298742 +0400 @@ -47,7 +47,7 @@ echo_command_at_execute, no_invisible_vars, noclobber, hashing_enabled, forced_interactive, privileged_mode, asynchronous_notification, interactive_comments, no_symbolic_links, - function_trace_mode, error_trace_mode, pipefail_opt; + function_trace_mode, error_trace_mode, pipefail_opt, jobs_m_flag; #if 0 extern int lexical_scoping;
