On 8/1/11 4:41 AM, dnade....@orange-ftgroup.com wrote:
> Hello
>
> I wanted to check a variable before attempting to divide something by it, so
> I wrote :
>
> echo $(( foo==0?0:something/foo ))
>
> And bash 2, 3 and up to 4.2.10 version sent me a "division by 0" error.
>
> So, I've tested a static version of the statement :
>
> $ echo $(( 0==0?0:1/0 ))
> -bash: 0==0?0:1/0 : division by 0 (error token is " ")
>
> It looks like the "division by 0" happens whatever the condition result.
> Shouldn't it happen only if condition result make the computing go that far
> (like, FWIW, in zsh) ?
Hmm...this looks like a precedence problem. I'll take a look.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU c...@case.edu http://cnswww.cns.cwru.edu/~chet/
