On 03/09/2011 02:54 PM, Chet Ramey wrote: >> >> For example: >> >> unset a; declare a="a"; [[ a -lt 3 ]]; echo $? >> bash: [[: a: expression recursion level exceeded (error token is "a") >> 1 >> >> Shouldn't the return code from this expression be 2, rather than 1? > > What does it matter? Failure is failure.
Except that [[ explicitly documents that 0 and 1 imply a syntactically valid expression, reserving $?==2 for catastrophic failure. The argument here is that infinite recursion is catastrophic and represents an invalid expression, and should not be confused with $?==1 meaning a valid but false expression. Similarly to expr(1) returning 0 and 1 depending on value for success, and > 1 on failure. -- Eric Blake ebl...@redhat.com +1-801-349-2682 Libvirt virtualization library http://libvirt.org
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