Hi together,
short: is there any way to get informed about unset local variable while
having option 'nounset' activated?
Long: the problem with 'local' is that variable declared this way are
visible inside the children, too. So the behaviour of option 'nounset'
depends on the way a function is called - either with a caller function
with the (locally) unset variable already set or without one.
Lets have a look at my example script:
-------------------------------------------------------
set -o nounset
function g()
{
echo "g: myvar=$myvar"
}
function f()
{
local myvar="test"
echo "f: myvar=$myvar"
g
}
f
-------------------------------------------------------
This way all is fine for bash but not for me since myvar is not set
inside g(). So if I call g() directly instead of f() then 'nounset'
gives me the error that I want.
This results into the question whether it is possible to get an error
for such situations, too?
Thanks in advance!
Kind regards
--
Heiko Nardmann
