I can't reproduce your problem. Does this work?: three=$(< data) echo three=$three
On Fri, Aug 6, 2010 at 12:31 PM, John Kelly <j...@isp2dial.com> wrote: > >>bash --version >>GNU bash, version 4.1.7(1)-release (i586-pc-interix3.5) > > #! /usr/local/bin/bash > > one=`cat data` > echo one=$one > > two=$(cat data) > echo two=$two > > >>one=abc >>./xs: command substitution: line 7: syntax error near unexpected token `)' >>./xs: command substitution: line 7: `cat data)' >>two= > > > Backquote command substitution works, but $(...) does not. Running it > with /bin/sh (the default system ksh) works fine. > >>$ sh xs >>one=abc >>two=abc > > > I built it like this: > >> >>CFLAGS="-O2 -march=i686" \ >>./configure \ >> --mandir=/usr/local/man \ >> --enable-process-substitution > > > Is this a bug or am I doing something stupid? > > > > -- > Web mail, POP3, and SMTP > http://www.beewyz.com/freeaccounts.php > > >
