On 06/07/2010 04:47 PM, Matthew Woehlke wrote: > But this does not: > $ echo "`echo \"you don\'t say\"`" > you don\'t say
\' is not special inside ``. If it is not special, then the \ is preserved on to the nested command. Bash's behavior matches POSIX here. > > I expected: > "you don't say" Then don't use \'. echo "`echo \"you don't say\"`" > > That is, I expected that \" -> " substitution would not happen inside > the ``'s outside of the context of the command substitution, since the > quotes do not need to be escaped in that context to be seen as quotes in > the substitution context. The quotes NEED to be escaped in the quoted command substitution context, since behavior is undefined if " quotes are not escaped inside "``". -- Eric Blake ebl...@redhat.com +1-801-349-2682 Libvirt virtualization library http://libvirt.org
signature.asc
Description: OpenPGP digital signature
