Version: bash-4.0.33
I'm trying to disable completion options from within a completion, but
I can't get `compopt +o <option>' to work.
Steps to reproduce:
1. Define functions/completions a, b, c & d:
_a() { COMPREPLY=(foo=); }
complete -F _a a
_b() { COMPREPLY=(foo=); }
complete -o filenames -F _b b
_c() { compopt -o filenames; COMPREPLY=(foo=); }
complete -F _c c
_d() { compopt +o filenames; COMPREPLY=(foo=); }
complete -o filenames -F _d d
2. Complete a, b, c & d. The option `-o filenames' escapes the `=' and I can't
disable it (d), although enabling it goes all right (c):
$ a <TAB>foo= ^C # Ok. Reference with -o filenames disabled
$ b <TAB>foo\= ^C # OK. Reference with -o filenames enabled
$ c <TAB>foo\= ^C # OK
$ d <TAB>foo\= ^C # Expected foo= (-o filenames disabled)
Regards,
Freddy Vulto
http://fvue.nl
