On Tue, Aug 25, 2009 at 02:40:24PM +0200, Oskar Hermansson wrote: > wget > http://www.kohanaphp.com/download?modules%5Bauth%5D=Auth&vendors%5Bmarkdown%5D=Markdown&languages%5Ben_US%5D=en_US&format=zip > > If the command is placed in a file instead, the file is successfully > downloaded: > wget `cat url.txt`
In the second version, the & characters in the URL are not seen by the bash parser, and therefore do not cause bash to see three separate commands. Bash just sees the one command, although word splitting would still be performed on the results of the substitution. (In simpler language, this means that if url.txt happened to contain any whitespace, you'd still get undesired behavior.) I can't address the reason bash is exiting, but in order to make your script work the way you intended, you should quote things: wget "http://...&foo=bar&baz=quux"; wget "$myurl" wget "$(cat url.txt)" # POSIX command substitution wget "`cat url.txt`" # old Bourne shell style wget "$(<url.txt)" # bash extension The double quotes in the first example will prevent the parser from treating the URL as three separate commands due to ampersands. In all five cases, the quotes will prevent word splitting of the URL or the substitution, so it would work even if you had spaces in your URL.
