This is my script: ================================================================= #!/bin/bash today_day=$(echo `date +"'%e %b %Y'"`)
echo $today_day tar -cvz --newer $today_day -f /mnt/usb_backup/backup/diff/backupFull_`date +%Y%m%d`.tgz /mnt/mirror80gb/Shared_Folder/ This is the debug: ================================================================= filer:/mnt/usb_backup/backup/test# bash -x ./jenea +++ date '+'\''%e %b %Y'\''' ++ echo ''\''25' Mar '2009'\''' + today_day=''\''25 Mar 2009'\''' + echo ''\''25' Mar '2009'\''' '25 Mar 2009' ++ date +%Y%m%d + tar -cvz --newer ''\''25' Mar '2009'\''' -f /mnt/usb_backup/backup/diff/backupFull_20090325.tgz /mnt/mirror80gb/Shared_Folder/ tar: Failed to open '/dev/sa0': Operation not supported filer:/mnt/usb_backup/backup/test# The problem is that the tar command would run only in the following syntax (see date part): ================================================================= tar -cvz --newer '22 Mar 2009' -f /mnt/usb_backup/backup/diff/backupFull_`date +%Y%m%d`.tgz /mnt/mirror80gb/ My question is: How can i pass the variable's content into the tar line so in the end it looks like this --- > '22 Mar 2009' Thank you. -- View this message in context: http://www.nabble.com/Bash-question-tp22404163p22404163.html Sent from the Gnu - Bash mailing list archive at Nabble.com.
