Configuration Information [Automatically generated, do not change]:
Machine: i686
OS: linux-gnu
Compiler: gcc
Compilation
CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i686' -DCONF_OSTYPE='linux-gnu'
-DCONF_MACHTYPE='i686-redhat-linux-gnu' -DCONF_VENDOR='redhat'
-DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -I.
-I. -I./include -I./lib -D_LARGEFILE_SOURCE -D_FILE_OFFSET_BITS=64 -O2 -g
-pipe -m32 -march=i386 -mtune=pentium4
uname output: Linux grid-ui.physik.uni-wuppertal.de
2.6.9-67.0.4.EL_SFS2.3_0smp #1 SMP Mon Jul 21 13:57:38 CEST 2008 i686 i686
i386 GNU/Linux
Machine Type: i686-redhat-linux-gnu
Bash Version: 3.2
Patch Level: 0
Release Status: release
Description:
A script containing some commands including hashmarks inside a
backtick operator fails to run correctly. The hashmark(s) seem to be
interpreted in a way that treats the rest of the line as comment, causing the
closing backtick to be skipped, and finally resulting in a unexpected EOF
parse error.
This behaviour only occurs using a bash (3.2) I compiled from source on
my
machine. I reproduced the problem on a 32bit- and on my 64bit-machine.
Repeat-By:
Execute the following line:
$ echo `seq -w 00 05 | sed -e 's# ##g'`
The expected output is:
0 1 2 3 4 5
$
In bash compilations showing the described problem, the output is
instead:
$ echo `seq -w 00 05 | sed -e "s# ##g"`
> (the bash is waiting for further input here... press CTRL+D)
bash: unexpected EOF while looking for matching ``'
bash: syntax error: unexpected end of file
$
