RMMM wrote:
RMMM wrote:
As far as I can tell, the variables $filenames and $filenames1 have the
same values. Yet, they
behave differently when used in an argument. Is there some hidden aspect
to a bash variable
that I'm not seeing?
I just figured out the problem. I was running this in a shell with
dircolors. Arggg!
doing
filenames=`ls --color=no mydir`
is all I needed to do. Well ... maybe there's some better way of getting the
filenames
that's immune to any invisible codes.
Guess 1:
command ls # avoids aliases, I think?
\ls # similar
env ls # also similar
(note: I belive --color=no is default behavior, probably you have an
alias that is adding --color=auto / --color=tty, which is why avoiding
the alias should work)
Guess 2:
files="$( for f in mydir/* ; do echo -n "${f#mydir/} " ; done )"
# uses bash glob expansion instead of ls, probably faster to boot
Guess 3:
files="$( cd mydir ; echo * )"
--
Matthew
Please do not quote my e-mail address unobfuscated in message bodies.
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