Configuration Information [Automatically generated, do not change]:
Machine: i486
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i486'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL
-DHAVE_CONFIG_H -I. -I../bash -I../bash/include -I../bash/lib -g -O2 -Wall
uname output: Linux sc.homeunix.net 2.6.25-rc8 #1 PREEMPT Fri Apr 4 08:56:07
BST 2008 i686 GNU/Linux
Machine Type: i486-pc-linux-gnu
Bash Version: 3.2
Patch Level: 39
Release Status: release
Description:
Hiya,
the doc says:
-t timeout Cause read to time out and return failure if
a complete line of input is not read within timeout
seconds. This option has no effect if read is not
reading input from the terminal or a pipe.
However, I find that it does have an effect on Unix or
TCP sockets, on /dev/random and other terminals than
"the" terminal.
So maybe a better wording could be: "This option has no
effect on regular files"?
Also, it may be good to specify that, if the timeout is
reached, bash will consume the input but will not put
that consumed input into the variable:
$ (printf xxxx; sleep 2; printf 'yyyy\n') | bash -c 'read -t1 a; echo "<$a>";
cat'
<>
yyyy
Also, is their a way to differenciate between "timeout"
and "eof"? Looks like the exit status is 1 in both
cases.
Like in:
sleep 1 | bash -c 'read -t2'
and
sleep 2 | bash -c 'read -t1'
Best regards,
Stephane
