> $ bash -ce '(false;echo foo);echo bar' > bar could i ask what the command line option '-e' mean? i did not find any explanation in bash's manual.
PS: [EMAIL PROTECTED] ~]# bash --version GNU bash, version 3.1.17(1)-release (x86_64-redhat-linux-gnu) Copyright (C) 2005 Free Software Foundation, Inc. > >
