if you use "$PWD" variable the assignment seems redundant too:)
On 11/14/07, Mike Stroyan <[EMAIL PROTECTED]> wrote: > > On Wed, Nov 14, 2007 at 01:11:12PM +0800, 龙海涛 wrote: > > it works. > > 3x very much. > > > > On Tue, 2007-11-13 at 21:51 -0700, Bob Proulx wrote: > > > > > 龙海涛 wrote: > > > > i want to store the current working dir to a variable, i write > > > > > > The most common way to save the present working directory to a > > > variable would be to use the $(...) form. > > > > > > test=$(pwd) > > > echo $test > > By the way, the variable "$PWD" has the same current directory value > as "$(pwd)" . > Assigning with > test=$PWD > can be quite a bit faster than using $(pwd) to execute the pwd builtin. > > $ s=$SECONDS;for (( i=1;i<10000;i++ )) ;do d=$(/bin/pwd);done;echo > $(($SECONDS-$s)) > 23 > $ s=$SECONDS;for (( i=1;i<10000;i++ )) ;do d=$(pwd);done;echo > $(($SECONDS-$s)) > 8 > $ s=$SECONDS;for (( i=1;i<10000;i++ )) ;do d=$PWD;done;echo > $(($SECONDS-$s)) > 0 > > The speed difference probably doesn't matter for most situations. > > -- > Mike Stroyan <[EMAIL PROTECTED]> > > >
