Frans de Boer <[EMAIL PROTECTED]> writes: > Okay, the function tries to alter the global var1 integer. But, the > result is that var1 is NOT changed.
Yes, because the function is executed in a subshell. > So, the result of the first echo > will be 0 > However, the next echo displays the changed var1 as being 1. At the > expense of losing the return value. You are not using the return value of the function but its output. The return value of a function is the exit status of the last executed command, and can also be set with return. The return value is available in $?. Andreas. -- Andreas Schwab, SuSE Labs, [EMAIL PROTECTED] SuSE Linux Products GmbH, Maxfeldstraße 5, 90409 Nürnberg, Germany PGP key fingerprint = 58CA 54C7 6D53 942B 1756 01D3 44D5 214B 8276 4ED5 "And now for something completely different." _______________________________________________ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
