Bash 3.1 - problem remains. Configuration Information [Automatically generated, do not change]: Machine: i686 OS: cygwin Compiler: gcc Compilation CFLAGS: -DPROGRAM='bash.exe' -DCONF_HOSTTYPE='i686' -DCONF_OSTYPE='cygwin' -DCONF_MACHTYPE='i686-pc-cygwin' -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/ locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -DRECYCLES_PIDS -I. -I/t mp/bash-3.1 -I/tmp/bash-3.1/include -I/tmp/bash-3.1/lib -O2 uname output: CYGWIN_NT-5.0 amd 1.5.19s(0.149/4/2) 20051229 16:10:48 i686 unknown unknown Cygwin Machine Type: i686-pc-cygwin
Bash Version: 3.1 Patch Level: 1 Release Status: release Description: Repeat-By: Fix: Read below. Hannu E K Nevalainen wrote: > New year greetings from Sweden! > > Below you find an issue that I have no intention/wish to discuss > further, I just wish to bring it forth to make it get a "known > issue" status. Reply-to set to bug-bash > > Expected result: > $ echo "a b c d e f g" | \ > ( while read first second ;do echo "got $first" ;done ) > got a > > The above works when IFS is set as in > $ echo -n "$IFS" | od -t x1z > 0000000 20 09 0a > ..< 0000003 > > > Problem: > If I understand the "$ help read" text correctly the following > variation should work, but it doesn't and additionally displays a > "totally off" error message. > > $ echo "a b c d e f g" | \ > ( IFS=" " while read first remainder ;do echo "got $first" ;done ) > bash: syntax error near unexpected token `do' > > > $ bash --version > GNU bash, version 3.00.16(1)-release (i686-pc-linux-gnu) > Copyright (C) 2004 Free Software Foundation, Inc. > > Tested on a two month old Gentoo and > on a fresh cygwin (www.cygwin.com) with the same bash version. > > /H /H -- _______________________________________________ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
