That's correct. The executable size would reflect the extra
operations required to compute the offset for the doubly dimensioned array.
Mike
At 03:40 PM 11/11/2009, Peter St. John wrote:
The difference between:
array1(1:60000)
array2(1:2, 1:30000)
would be reflected in the size of the executable, not the size of the data.
Right?
Peter
On Wed, Nov 11, 2009 at 9:01 AM, Michael H. Frese
<<mailto:michael.fr...@numerex-llc.com>michael.fr...@numerex-llc.com> wrote:
At 06:43 PM 11/10/2009, Larry Stewart wrote:
On Tue, Nov 10, 2009 at 8:30 PM, amjad ali
<<mailto:amja...@gmail.com>amja...@gmail.com> wrote:
HI,
suppose we have four arrays with same number of elements say
60000., but different dimensions like:
array1(1:60000)
array2(1:2, 1:30000)
array3(1:2, 1:300, 1:100)
array4(1:4, 1:15, 1:10, 1:100)
Does each of these arrays in fortran will occupy same amount of memory?
For sending/receiving each of these, Does MPI has the same (or
nearly same) overhead? or any significantly different overhead is
involved in handling each of these arrays (by MPI)?
They should take the same amount of space and have nearly identical
transfer times with MPI.
(If you send the whole thing)
-L
Those four array descriptors can all apply to exactly the same
space, via an 'equivalence' statement. They are all laid out in
memory just like array1.
Thus, they can each be transmitted by exactly the same MPI send.
Mike
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