"Robert G. Brown" <[EMAIL PROTECTED]> writes: > I think that matrix allocation per se is contiguous because of how and > where it occurs at the compiler level. Immediate matrices allocated > like a[10][10] are just translated into displacements relative to the > stack pointer, are they not?
It depends. You're not guaranteed per se that they'll be allocated on the stack, though in practice they are. > Global/external matrices at the a[10][10] > are prespecified in the data segment of the program, Depending on the particular OS. Certainly that's the usual model. > The only place where it might not be true is when one dynamically > allocates memory for a **matrix. There, if you loop through malloc > calls, there is no guarantee that they return contiguous blocks An vector of pointers to vectors is not a matrix. :) It acts a bit like one, but that's guaranteed NOT to be contiguous allocation because malloc will at the very least add the (invisible to the programmer) malloc headers etc. -- Perry E. Metzger [EMAIL PROTECTED] _______________________________________________ Beowulf mailing list, Beowulf@beowulf.org To change your subscription (digest mode or unsubscribe) visit http://www.beowulf.org/mailman/listinfo/beowulf
