-----Original Message-----
From: Chas. Owens [mailto:[EMAIL PROTECTED]
Sent: Thursday, October 16, 2008 2:36 PM
To: sanket vaidya
Cc: [email protected]
Subject: Re: if condition question
On Thu, Oct 16, 2008 at 04:54, sanket vaidya <[EMAIL PROTECTED]>
wrote:
snip
> Now when I write the same if condition in program as below, I get warning
> along with output.
snip
> $string eq "test" ? print "correct" : "";
snip
> Useless use of constant in void context at line 5.
snip
>What the ternary operator* is saying is roughly equivalant to
>if ($string eq "test") {
print "correct"
>} else {
""
>}
>>That empty string by itself is what is causing the warning. What you
really want to say is
>>print $string eq "test" ? "correct" : "";
How can I write
if ($string eq "test") {
print "correct"
} else {
die "others"
}
In above way?
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