On Wed, Mar 19, 2008 at 9:32 AM, Rajanikanth Dandamudi
<[EMAIL PROTECTED]> wrote:
> Hi All,
>
> I would like to understand the behavior of the following program:
snip
> my @a=qw(1 0 0 0 0 0 0 1);
> my @b=qw(0 0 0 0 0 0 0 0);
snip
> I would like to understand why $f does not have any value in the first
> print statement. perl version being used is v5.8.0
snip
Because you are not using a numeric xor, you are using an string xor.
The qw// operator returns a list of strings:
my @a = ('1', '0', '0', '0', '0', '0', '0', '1');
You might want to read up on bitwise string operators*, in the
meantime, I would suggest not using qw// when you are dealing with
numeric values or ensure that your values are numeric by adding 0 to
them before using an operator that has both numeric and string
versions. By the way, a value is being printed, you just can't see it
because it is character \x{01} (start of heading).
* http://perldoc.perl.org/perlop.html#Bitwise-String-Operators
--
Chas. Owens
wonkden.net
The most important skill a programmer can have is the ability to read.
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