Re: hash of hash - copy

[Frank Bax]

At 03:17 PM 11/4/05, Jeff 'japhy' Pinyan wrote:

On Nov 4, Frank Bax said:
$aSuit{0}{'a'} = 'A';
$aSuit{0}{'b'} = 'B';
$aSuit{0}{'c'} = 'C';
$aSuit{1}{'a'} = 'D';
$aSuit{1}{'b'} = 'E';
$aSuit{1}{'c'} = 'F';

Now I want to make $aSuit{1} a copy of $aSuit{0}
        %aSuit{1} = %aSuit{0};

Well, $aSuit{1} = $aSuit{0} would make $aSuit{1} and $aSuit{0} IDENTICAL. 
Meaning, when $aSuit{0}{a}, $aSuit{1}{a} changes too.  If you don't want 
that, you can do:

  %{ $aSuit{1} } = %{ $aSuit{0} };

But that only works one level deep.


One level deep works for me!  But IDENTICAL does not.  Thanks for quick 
response (David too).


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