>Timothy Johnson wrote:
>
>>It depends on what you're trying to do. if $hashRef is a hash
>>reference, then the correct syntax would be:
>>
>> $hashRef->{$key} = $value;
>>
>>or
>>
>> %{$hashRef}{$key} = $value;
>>
>>What you're saying below is something like:
>>
>>-- Take $hashRef and dereference it to %HASH1 (I'm giving it a name
>> for clarity)
>>-- Then use %HASH as a reference to another hash, let's say %HASH2.
>>-- Finally, use the -> operator to get the $key key of the hash
%HASH2.
>>
>>
>>If this doesn't answer your question, then you will need to give us
some
>>examples.
>>
>
>Thanks for the quick response, Timothy. Here is the function in
question
>and a representative calling sequence....
>
>Calling sequence...............
># Form buffer
>my(%FIELDS,$query,$code,$checks);
># Get data from form (get_form_data_1 is local to this program) !!!!
>&get_form_data_1(\%FIELDS);
>Function........................
>sub get_form_data_1 {
> my($hashRef) = @_;
>
<snip>
> %{$hashRef}->{$key} = $value;! # Enter the value in the hash
><----- Deprecated stmt
> print "get_form_data_1: Setting $key to [$value]<br>"; #Debug....
> }
>}
It looks like the syntax you are looking for is
$hashRef->{$key} = $value;
When you use the -> operator, you are indirectly accessing the value for
the hash POINTED TO by the scalar on the left side. So you're basically
saying that
$hashRef->{$key}
is the key "$key" of the hash that $hashRef is pointing to.
FYI, I should correct the typo in my first email. If you want to use
the %{$hashRef} syntax, then it should be:
${$hashRef}{$key}
NOT
%{$hashRef}{$key}
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