Hi Friends,
I have the below code.
#!/usr/local/perl5.6.1/bin/perl
print STDOUT "===============================Before system
call===========================\n\n";
system("ls -al");
print STDOUT "\n\n===========================After System
Call============================\n\n";
When I execute the code from command prompt, the output is,
===============================Before system
call===========================
total 8
drwxr-xr-x 2 mkodiche cisco 96 Dec 23 21:54 .
drwxr-xr-x 4 mkodiche cisco 1024 Dec 23 19:36 ..
-rw-r--r-- 1 mkodiche cisco 465 Dec 23 22:00 a.txt
-rwxrwxr-x 1 mkodiche cisco 279 Dec 23 22:00 background.pl
-rwxrwxr-x 1 mkodiche cisco 92 Dec 23 21:53 loop.pl
===========================After System Call============================
But, when I redirect the output to a file, the contents of the file are
total 6
drwxr-xr-x 2 mkodiche cisco 96 Dec 23 21:54 .
drwxr-xr-x 4 mkodiche cisco 1024 Dec 23 19:36 ..
-rw-r--r-- 1 mkodiche cisco 0 Dec 23 22:34 a.txt
-rwxrwxr-x 1 mkodiche cisco 279 Dec 23 22:00 background.pl
-rwxrwxr-x 1 mkodiche cisco 92 Dec 23 21:53 loop.pl
===============================Before system
call===========================
===========================After System Call============================
As seen above, the system call output is displayed first and then the
print statement.
Why it is behaving strangely? Any idea?
Thanks is advance,
Mallik.
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