On Aug 4, Perl said: >die "You must enter an argument. \n" if $#ARGV <0;
I'd suggest using: die ... if @ARGV == 0; because it's easier to read and understand. >$logfile = chomp ($ARGV); Is that really your code? That doesn't make any sense to me. I think you meant: $logfile = $ARGV[0]; There's no reason to chomp() here, and besides, chomp() doesn't return the modified string, it returns a number. -- Jeff "japhy" Pinyan % How can we ever be the sold short or RPI Acacia Brother #734 % the cheated, we who for every service http://japhy.perlmonk.org/ % have long ago been overpaid? http://www.perlmonks.org/ % -- Meister Eckhart -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
