Re: A better way, a perl way?

[Jeff 'japhy' Pinyan]

On Jan 22, Jerry Preston said:

>I am looking for a better way, a perl way for the following:
>
>    foreach ( @data ) ) {
>      s/^ //;
>      $data_[ $jp++ ] = $_;
>    }

You do realize that you're modifying the elements in @data as well, right?
So that, unless $jp starts at some value other than 0, @data_ and @data
are exactly the same.

If you DON'T want that, you'd have to do:

  for (@data) {
    (my $copy = $_) =~ s/^ //;
    push @data_, $copy;
  }

Or something to that effect.  Here's a one-liner:

  @data_ = map { (my $copy = $_) =~ s/^ //; $copy } @data;

-- 
Jeff "japhy" Pinyan      [EMAIL PROTECTED]      http://www.pobox.com/~japhy/
RPI Acacia brother #734   http://www.perlmonks.org/   http://www.cpan.org/
<stu> what does y/// stand for?  <tenderpuss> why, yansliterate of course.
[  I'm looking for programming work.  If you like my work, let me know.  ]


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