You have to compile the input. Try using eval.
It should look something like:
while (<STDIN>) {
$calc= eval $_;
print $calc."\n";
last;
}
But, don't forget to catch errors.
Sasha
> -----Original Message-----
> From: Jacques Lederer [mailto:[EMAIL PROTECTED]]
> Sent: Sunday, January 19, 2003 12:45 PM
> To: [EMAIL PROTECTED]
> Subject: scalar number or string?
>
>
> Hello,
> When you write
> $calc=3+5-2;
> print $calc."\n";
> you get 6. (number, not the string "3+5-2")
> When you write
> while (<STDIN>) {
> $calc=$_;
> print $calc."\n";
> last;
> }
> if you run that last one and type 3+5-2, you get
> 3+5-2.(string "3+5-2", not the number 6)
> Why is it so? And how can I get it to calculate the thing?
> I have gone through all of the perldoc perlfaqs. Maybe the
> answer is so simple that I don't see it. I am just trying to
> build a simple calculator. I have found a rather complicate
> solution which works, but there must be a very simple
> solution, isn't it?
>
> Jacques L
>
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