You should always include "use strict" and "use warnings" when you are
writing code. Take a look at the subryoutine and you will see:
$temp = $_[0] means that temp is now a reference to @array
$temp[0] is the first element of the array @temp, which was created when you
used the element
$$_[0][0] would then be the same as $$temp[0]
But to make sure that you can't make mistakes like this when dereferencing
an array, put braces around the reference:
${$_[0]}[0]
${$temp}[0]
Also, if you want to make it even easier to read, try this notation:
$temp->[0]
which is the same as:
${$temp}[0]
P.S. The same works for hashes. $temp->{key} accesses an element of the
hash referenced by $temp
-----Original Message-----
From: Paul Kraus [mailto:[EMAIL PROTECTED]]
Sent: Monday, January 06, 2003 1:30 PM
To: Perl
Subject: passing array ref to subroutine
I don't understand why the output of the two print statements inside the
subroutine is different. The one only prints the new line.
#!/usr/bin/perl -w
@array=qw/paul david kraus/;
$arrayref=\@array;
print "$arrayref\n";
print "$$arrayref[0]\n";
&suby($arrayref);
sub suby {
$temp=$_[0];
print "$$_[0][0]\n";
print "$temp[0]\n";
}
Paul Kraus
Network Administrator
PEL Supply Company
216.267.5775 Voice
216-267-6176 Fax
www.pelsupply.com
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