"Jensen Kenneth B Sra Afpc/Dpdmpq" <[EMAIL PROTECTED]> wrote in
message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Yes
>
> ($org) = ($1 =~ s/,//g);
>
> Is the same as
> $1 =~ s/,//g;
> $org = $1;
>
Actually not quite.
($org) = ($1 =~ s/,//g);
is assigning the result of the =~ operator to $org. This is the number of
times the regex matched in the object string: in this case '1', because
there is one comma.
To abbreviate
$1 =~ s/,//g;
$org = $1;
you would have to write:
$org = ($1 =~ s/,//g, $1);
but then this isn't what was wanted anyway :-}
Cheers,
Rob
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