On Oct 17, Mandar Rahurkar said:
>> >> @new = grep { ! /^$no/ } @list;
>> >> @new = grep !/^\Q$no/, @list;
>> >
>> >thanks for your prompt reply...however this does not work..
>> >program does not generate any output...
>>
>> What program? Please show us the code you're (now) using.
>
>$spkr=shift(@ARGV);
>@list = `ls`;
>@n_train_list = grep !{/^$spkr/}, @list;
>print @n_train_list;
You're messing up your grep(). (And you don't have warnings on, or else
you'd be given some warnings that might help you figure things out.)
grep() comes in two flavors:
grep { CODE } LIST
and
grep EXPR, LIST
The first form has no comma, the second does. Your code is the 2nd form,
and you're logically negating a hash reference. You want either
grep { !/^$spkr/ } @list;
or
grep !/^$spkr/, @list;
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
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