John Ross wrote:
> Thank you to all of you who responded to my question about pasing hashes
> into a function. The -> operator did the trick.
> My problem was that I thought once I passed the hash in, I could
> dereference it That doesn't appear to work like I expected.
>
> sub mod_hash {
> my $hash_ref = @_;
> my %hash = %$hash_ref;
>
>
> $hash{key} = 0;
>
>
> etc,etc,etc.
>
> It appears that that just makes a local copy of the hash, then disposes of
> that copy at the end of the subroutine. I think I kind of understand why
> this doesn't work.
>
> Thanks again for you help,
>
> John
>
change:
my $hash_ref = @_;
to:
my ($hash_ref) = @_;
but once you deference it and assign it to another hash like:
my %hash = %$hash_ref;
it's no longer acting on the hash ref. in other word, when you do:
$hash{key} = 0;
it will NOT affect $hash_ref anymore.
david
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