On Feb 12, Steven M. Klass said:
>&Somefunction($var1, \@arry)
>
>sub SomeFunction {
> my $var = $_[0]; # XXX you were missing a ; here
> my $array = shift;
Uh, $array and $var have the same value now. shift() removes the first
element from an array (defaulting to @_) and returns it. The first
element of @_ is $_[0], which is $var1.
Saying
my $var = $_[0];
is not the same as
my $var = shift;
The first one does NOT remove the element from @_; the second one DOES.
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
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