ok.. I'm sorry... I was an idiot, i wasnt thinking, and i am sorry
*cringe* this will extract the string (and the brackets)...
($b) = $a =~ /\(.+\)/g)
--
Deen Hameedd, Accidental Programmer [EMAIL PROTECTED]
---------- Forwarded message ----------
Date: Sat, 26 Jan 2002 18:30:56 +0530 (IST)
From: Deen Hameed <[EMAIL PROTECTED]>
To: Hubert Ian M. Tabug <[EMAIL PROTECTED]>
Cc: Perl <[EMAIL PROTECTED]>
Subject: Re: string manipulation
something like this should work...
(@somearray) = split(/\(.*\)/, $a);
On Sat, 26 Jan 2002, Hubert Ian M. Tabug wrote:
> Hi,
>
> Given the string $a = "xxx xxx xxx xxx xxx xxx xxx (Jan 12
> 1990 ......)", I wan't to selectively extract that part of the string
> having the (Jan 12 1990 ...) and store it in an array. Can someone guide
> me?
>
>
> Thanks,
> Hubert
>
>
--
Deen Hameedd [EMAIL PROTECTED]
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