In perl:
(($n < 1) || ($n > 12)) is true when n is less than 1 or if n is greater
than 12. Try this:
for my $n (-5..17){
if (($n < 1) || ($n > 12)) {
print "True for \$n = $n\n"
} else {
print "False for \$n = $n\n"
}
}
Double check your logic. Are you sure you're using integers? (0.99999
is less than 1 after all).
- Johnathan
> The following conditional expression tests whether the value of
> $number1 is negative or greater than 12:
>
> (($number1 < 1) || ($number1 > 12))"
>
> Shouldn't this test whether the number is 0, negative, or > 12? Is
> this unique to the way Perl uses numbers?
>
> TIA,
> - NP
>
> _________________________________________________________________
> MSN Photos is the easiest way to share and print your photos:
> http://photos.msn.com/support/worldwide.aspx
>
>
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
