On Jan 13, rabs said:
>#!/usr/bin/perl-w
>print "please enter a word then press enter\n";
>@a= <STDIN>;
>$L =@a;
>for ($i=0; $i<=$L; $i++){
>print $a[$i];
>}
Your loop should be
for ($i = 0; $i < $L; $i++) { ... }
Notice <= should be <. It should also be noted that the idiomatic way of
looping over an array is like so:
for (@a) {
# do something with $_
}
So your code could be:
@a = <STDIN>;
for (@a) { print }
And, since we're on the subject, you could rewrite those as:
while (<STDIN>) { print }
>print "\n there are $L varibles in the hash";
>print "\n why wont $a[$0] print out "
The data structure is not a hash, it is an array. And $0 is the variable
holding your program's name. I believe you meant $a[0].
>The program prints out
>
>have
>underwater
>weapons
I bet you're on a windows machine, and windows has a notorious habit of
"eating up" the first line of output. :(
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
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