C:\users>perl -e "$A=qq(a);for(0..285074){$A++}print qq($A\n);"
perl
C:\users>perl -e "$A=qq(a);for(0..28){$A++}print qq($A\n);"
ad
C:\users>perl -e "$A=qq(a);for(0..2){$A++}print qq($A\n);"
d
C:\users>perl -e "$A=qq(a);for(0..1){$A++}print qq($A\n);"
c
C:\users>perl -e "$A=qq(a);for(0){$A++}print qq($A\n);"
b
C:\users>perl -e "$A=qq(a);for(0..10){$A++}print qq($A\n);"
l
C:\users>perl -e "$A=qq(a);for(0..26){$A++}print qq($A\n);"
ab
C:\users>
etc etc etc
:-)
Luke
On Thu, 10 Jan 2002, zentara wrote:
> Hi,
> I saw this on perlmonks.org.
> I can't understand how it works.
> Can anyone enlighten me?
>
> #!/usr/bin/perl
> my $A="a";
> for(0..285074){$A++;}print"$A\n";
>
>
>
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