>Micheal Fowler wrote:
>Use fork and exec:
>
> my $pid = fork();
> die("Unable to fork: \l$!.\n") unless defined($pid);
> if ($pid) {
> # Get the window title.
> } else {
> exec($program);
> }
>It's not guaranteed the child will be ready when then parent is reaches the
>code to query the window title. You will likely have to poll for the data
>you want, or sync up the parent and child processes.
OK, I'm just learning, so I wanted to try this fork statement.
#!/usr/bin/perl
use warnings;
my $program = 'ls';
my $pid = fork();
die("Unable to fork: \l$!.\n") unless defined($pid);
if ($pid) {
print "$pid\n";
} else {
exec($program);
}
Now what is confusing me, is the if-else behavior.
When I run this program sometimes just the pid is
printed, then sometimes the pid AND the ls is printed.
The ls is never printed alone.
What's happening in the if-else statement that is
allowing both to be executed? Is it just accidental
timing, that the pid disappears after printing, but
before the else statement is evaluated?
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