for my $i (1 ... $num) {
s/$pat/$pat+$i/;
}
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Jason Ledbetter
Data Conversion Specialist
Perl Monk and Ascii Ninja
Cadmus Professional Communications
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- regex question with s/// Bradford Ritchie
- Re: regex question with s/// Jason Ledbetter
- Re: regex question with s/// Jason Ledbetter
- RE: regex question with s/// Bob Showalter
