Hi,

You have to create a state machine, at start you can have something in the serial buffer and you will lose receiver sync..


Java example:

   privateenum  Stage {
        FIND_STAGE1,
        FIND_STAGE2,
        FIND_STAGE3,
        FIND_STAGE4,
        FIND_STAGE5
    }

    public  void  test() {
        Stage currentStage = Stage.FIND_STAGE1;
        ByteBuffer buffer = ByteBuffer.allocate(255);
        while  (true) {
            buffer.clear();
            int  count = readCom(buffer);
            if  (count < 1) {
                continue;
            }
            for  (int  i = 0; i < count; i++) {
                int  j = buffer.get(i) & 0xff;
                switch  (currentStage) {
                    case  FIND_STAGE1:
                        if  (j == 0x10) {
                            currentStage = Stage.FIND_STAGE2;
                        }
                        break;
                    case  FIND_STAGE2:
                        if(j == 0x11){
                            currentStage = Stage.FIND_STAGE3;
                        }else{
                            currentStage = Stage.FIND_STAGE1;
                        }
                        break;
                    case  FIND_STAGE3:
                        if(j == 0x12){
                            currentStage = Stage.FIND_STAGE4;
                        }else{
                            currentStage = Stage.FIND_STAGE1;
                        }
                        break;
                    case  FIND_STAGE4:
                        if(j == 0x13){
                            currentStage = Stage.FIND_STAGE5;
                        }else{
                            currentStage = Stage.FIND_STAGE1;
                        }
                        break;
                    case  FIND_STAGE5:
                        System.out.println("received header: 
0x10,0x11,0x12,0x13");
                        System.out.println("received data: "+j);
                        currentStage = Stage.FIND_STAGE1;
                        break;
                }

            }
        }
    }


ArSi



------------------------------------------------------------------------

*From:* David Howlett
*Sent:* Friday, April 21, 2017 6:18PM
*To:* Beagleboard
*Subject:* [beagleboard] Repeatable bug where beaglebone black loses bytes from
it's serial connection.


I have spent about two days tracking down an issue in one of my machines. I am streaming pressure readings from an i2c pressure sensor to a PC at high speed. I have reduced the problem to a small test case. To replicate the fault I connect the beaglebone black to a PC, connect to it with serial over the micro USB port, login and launch a command that streams data fast. On the PC run a program that collects the streamed data more slowly than it is being created.

importserial

x = serial.Serial('COM15')
to_send =b'\x03yes HelloWorld\n'
x.write(to_send)
while True:
     received = x.readline()
     ifreceived !=b'HelloWorld\r\n':
         print(received)

The python program above prints lines like:

b'ld\r\n'
b'HelloWoroWorld\r\n'
b'HelloWorldorld\r\n'
b'HelloWorldorld\r\n'
b'ld\r\n'
b'ld\r\n'
b'ld\r\n'
b'ld\r\n'
b'ld\r\n'
b'ld\r\n'
b'HelloWoroWorld\r\n'
b'ld\r\n'
b'HelloWlloWorld\r\n'
b'ld\r\n'
b'HelloWorldorld\r\n'

At about 4 lines per second. If I set the program on the beagle bone to stream slowly then this issue goes away. It appears to be an issue with a buffer filling up somewhere between the output of the yes command and reading bytes from the windows API. The correct behaviour is that the yes command should be stopped when the buffer is full to prevent the loss of data, then allowed to continue when there is space in the buffer again. I observe that the streaming command (in this case yes) is stopped but there is still data loss happening somewhere.

I wrote this in python because it is the language I am most comfortable in but if you needed me to I could rewrite the example in some other language. To run the program shown above you will need pyserial and you will need to change 'COM15' to be whatever the port is called on your computer.


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