Hi,
I've an application that has both a command-line and a version with a graphical
user interface (GUI). These are located in directories src/non_gui and src/gui.
The GUI version should only be built if the option --with-gui is added when
running configure. If the user does not add that option, then the GUI version
should not be built and I assume (perhaps incorrectly) that I should not make a
Makefile for it. If this is the case, how do I do this conditionally?? Or how
else do I only build the GUI version when the option is given to configure.
I currently have at the bottom of my configure.in, the following, which despite
being commented out, you can see my intentions. I was intending only creating a
Makefile if the option is given. My idea requited that AC_OUTPUT is called
twice, which I believe is wrong.
Related to this, how do I give a different set of options to CC when building
the GUI version? I've just started to use wXWindows, an example of which says
the following options are required.
g++ hworld.cpp `wx-config --libs` `wx-config --cflags` -o hworld
Anyway, here is the end of my configure.in. Any suggesions to achieve what I
want?
AC_OUTPUT([\
Makefile \
src/Makefile \
src/non_gui/Makefile \
src/gui/Makefile \
man/Makefile \
examples/Makefile \
docs/Makefile \
docs/html-docs/Makefile \
docs/html-docs/jpgs/Makefile \
docs/qex-december-1996/Makefile \
docs/theory/Makefile \
docs/Makefile ])
dnl if test "x$with_gui" = "xyes"; then
dnl AC_OUTPUT([src/gui/Makefile])
dnl fi
--
Dr. David Kirkby PhD,
email: [EMAIL PROTECTED]
web page: http://www.david-kirkby.co.uk
Amateur radio callsign: G8WRB
