You'd have to use 2 queues.  After 5 minutes, exit queue 1, enter queue 2 that 
has a different periodic announcement.  Since everybody leaves queue 1 after 5 
minutes, they will enter queue 2 in the same order as they left queue 1.



Mike

-----Original Message-----
From: [email protected] 
[mailto:[email protected]] On Behalf Of Carlos Chavez
Sent: Wednesday, January 12, 2011 2:15 PM
To: Asterisk
Subject: [asterisk-users] Queue periodic announce...

        Is there a way to play a different message than the periodic announce 
after a certain time?  I have been asked by a customer to do something like 
this:

The user enters the queue.
We play position and periodic announce every 60 seconds.
If user has waited for more than 5 minutes then play a message with option to 
leave a voicemail

        This means that I would have to be able to play a different message 
after five minutes.  I thought I could solve this by having the user leave the 
queue after 5 minutes, play the message with the option for voicemail and then 
reinserting them into the queue but I cannot find a way to put the user back in 
the same position they were when the timeout occurred.  Any ideas on how to 
implement this?  We are using Asterisk
1.6.2.15 with Queuemetrics.

--
Telecomunicaciones Abiertas de M xico S.A. de C.V.
Carlos Ch vez Prats
Director de Tecnolog a
+52-55-91169161 ext 2001


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