Okay, I was getting some wires crossed over this in that I
conflated the special case of converting binary data to a hexadecimal character
string and the general case where binary data in (putatively) packed decima
format is converted to a decimal character string.I’ve written code to perform
both tasks many times and am actually a pretty competent (accomplished, even)
Mainframe assembler programmer but I’m also at the end of a long sabbatical
leave and some rust build-up is inevitable I guess.I’m excited to put my
talents back into income-generating use once more.
Sorry for any confusion y’all Keven
On Fri, Apr 13, 2018 at 9:17 AM -0500, "Seymour J Metz" <[email protected]> wrote:
Of course; the standard way to convert binary to hex is the UNPK/TR with a one
byte pad.
--
Shmuel (Seymour J.) Metz
http://mason.gmu.edu/~smetz3
________________________________________
From: IBM Mainframe Assembler List on behalf of Martin Ward
Sent: Friday, April 13, 2018 10:13 AM
To: [email protected]
Subject: Re: SDWA - SDWACMPC conversion
On 13/04/18 15:02, Seymour J Metz wrote:
> Unpacking x'0123' gives you x'F0F132'; the OI then gives you
> x'F0F1F2'; what you want is x'F0F1F2F3'. Or with an UNNPK length of 4
> you get x'F0F0F1F2'; still not what you want.
Suppose the byte after the X'0123' is X'xy' (where x and y are
any hex digits).
Unpacking X'0123xy' (with a source length of 3 and a destination
length of 5) gives you X'F0F1F2F3yx' which, when you drop
the last byte, gives you what you want.
This assumes that there is an addressable byte immediately after X'0123'
For a general solution, copy the source field to a sufficiently
large work area before unpacking.
--
Martin
Dr Martin Ward | Email: [email protected] |
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G.K.Chesterton site:
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