Hello, I have a question about grep, okay yes is not direct Arch but I not find a information and here on list sure some profis with grep.
The folder structure: content/de/blog/*.md content/fr/blog/*.md content/en/blog/*.md content/ru/blog/*.md To know which articles I have translate I grep through dates: grep -e "2019-10-1" content/blog/de (for the dates between 10 and 19) I become: grep -e "2019-10-1" content/de/blog/* content/de/blog/file1.md:date: 2019-10-10 content/de/blog/file2.md:date: 2019-10-12 content/de/blog/file3.md:date: 2019-10-14 content/de/blog/file4.md:date: 2019-10-16 Now is my question, How can I do the same in the other folders and all those that exist with the same date are hidden and when no file is present give out the file which is missing in other folders sort by date. The name of file is sure other, but the date is ever the same. grep -e "2019-10-1" content/en/blog/* No output > all files translated grep -e "2019-10-1" content/fr/blog/* content/de/blog/file4.md:date: 2019-10-16 > file is missed grep -e "2019-10-1" content/ru/blog/* content/de/blog/file3.md:date: 2019-10-14 > file is missed content/de/blog/file4.md:date: 2019-10-16 > file is missed Grep to the first folder (de) as a comparison to the others (en,fr,ru). I had try it with diff but it want not work. Would be great there is a idea. Thank you for help. Silvio
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