Perhaps the following will achieve your goal:
{% for source in lookup('together', containers, apps, wantlist=True) %}
container={{ source.0 }}
app={{ source.1 }}
{% endfor %}
On Wed, Dec 16, 2015 at 2:19 PM, Abel Makkonen Tesfaye <
[email protected]> wrote:
> I plan to use it in a template like so:
>
> {% for source in services %}
>
> container={{source.container}}
>
> app={{source.app}}
>
> {% endfor %}
>
>
> On Wed, Dec 16, 2015 at 12:03 PM, Matt Martz <[email protected]> wrote:
>
>> How do you plan on using this data. Maybe there is a different way to
>> achieve your result, because it won't be easy or straight forward to get
>> what you want.
>>
>> Maybe with_together on a task could give you what you want instead:
>>
>> - debug: var=item
>> with_together:
>> - apps
>> - containers
>>
>>
>>
>> On Wed, Dec 16, 2015 at 1:43 PM, <[email protected]> wrote:
>>
>>> I have 2 arrays
>>>
>>>
>>> "containers": [
>>> "ContainerA",
>>> "ContainerA",
>>> "ContainerB",
>>> "ContainerB"
>>> ]
>>>
>>> "apps": [
>>> "app2",
>>> "app1",
>>> "app2",
>>> "app1"
>>> ]
>>>
>>>
>>> I would like to merge them into an array of dictionaries like this ( I
>>> assume with set_fact ):
>>>
>>> services:
>>> - { container: 'ContainerA', app: 'app2' }
>>> - { container: 'ContainerA', app: 'app1' }
>>> - { container: 'ContainerB', app: 'app2' }
>>> - { container: 'ContainerB', app: 'app1' }
>>>
>>>
>>> How can I do that?
>>>
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>>
>>
>>
>> --
>> Matt Martz
>> @sivel
>> sivel.net
>>
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>
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--
Matt Martz
@sivel
sivel.net
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