Hi,
This is a simple application which sends group sms (a group consist
only 5 phone numbers )and i have registered a Broadcast to announce
when an sms is send .here i need to display the number to which the
sms is send ,how to do that
here is my code
# In onCreate()
button is pressed it triggers an onClick event and sends the group
sms
public void onClick()
{
for (int j = 0; j<phonenos.length;j++)
{
sendSMS(phonenos[j],mess);
}
}
String SENT = "SMS_SENT";
private void sendSMS(String phoneNumber, String message)
{
Intent ss=new Intent(SENT);
ss.putExtra("phno1", phoneNumber);
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0,ss,
0);
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phoneNumber, null, message, sentPI, null);
}
public void onStart()
{
super.onStart();
br_send=new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS sent
",
Toast.LENGTH_SHORT).show();
Log.v(TAGS,"intent :"+arg1.getExtras
().getString("phon1")); //*****error *****
}
}
};
registerReceiver(br_send,new IntentFilter(SENT));
}
public void onStop()
{
super.onStop();
unregisterReceiver(br_del);
}
an error is thrown at arg1.getExtras().getString("phon1") Log
statement ,is this a right approach to display the number to which
the sms is send
error is
java.lang.RuntimeException: Error receiving broadcast Intent
{ action=SMS_SENT } in seaant.android.panicmessag...@437489e8
Caused by: java.lang.NullPointerException
Help me to solve this error
Thanks
Ganesh
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