Bob was asking for the string representation of an integer IP number. His solution is correct, straightforward and does not require the instantiation of three intermediate objects just for getting a simple string. Your one-liner however creates a BigInteger, then a byte array and finally an instance of InetAddress which still is not a string. It's toString method may or may not return the resolved host name in addition to the IP number string representation. That's not quite the original requirement.
On Tuesday, February 19, 2013 9:43:35 AM UTC-6, Larry Meadors wrote: > > On Tue, Feb 19, 2013 at 8:05 AM, bob <[email protected]<javascript:>> > wrote: > > Why do you say that? > > Because it's a ridiculously obfuscated solution to a problem with a > simple one-line solution: > > InetAddress address = > InetAddress.getByAddress(BigInteger.valueOf(actualIpAddressAsInt).toByteArray()); > > > > Larry > -- -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en --- You received this message because you are subscribed to the Google Groups "Android Developers" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
