RTFT
http://developer.android.com/training/displaying-bitmaps/load-bitmap.html
On Monday, December 10, 2012 10:42:37 AM UTC-5, snowdream wrote:
>
> Hi,everyone.
> if i want to get a large image (eg.a image which size is 2M or
> larger.)from url, i use the folllowing code ,and get the exception ."Out of
> Memory".
> Any good idea?
> Thank you.
>
>
> private Bitmap getBitmapFromUrl(String url) {
> Bitmap bitmap = null;
>
> try {
> URL imagePath = new URL(url);
> HttpURLConnection conn =
> (HttpURLConnection)imagePath.openConnection();
> conn.setConnectTimeout(CONNECT_TIMEOUT);
> conn.setReadTimeout(READ_TIMEOUT);
> conn.connect();
> InputStream is = (InputStream) conn.getContent();
> if (is != null) {
> // bitmap = getBitmapFromInputStream(is, width, height);
> bitmap = BitmapFactory.decodeStream((InputStream)
> conn.getContent());
> }
> } catch(Exception e) {
> e.printStackTrace();
> }
>
> return bitmap;
> }
>
>
> public static Bitmap getBitmapFromInputStream(InputStream is, int
> width, int height){
> Bitmap bitmap = null;
> if (null != is ) {
> BufferedInputStream bis = new BufferedInputStream(is);
>
> BitmapFactory.Options opts = null;
> if (width > 0 && height > 0) {
> opts = new BitmapFactory.Options();
> opts.inJustDecodeBounds = true;
> BitmapFactory.decodeStream(is, null, opts);
>
> // 计算图片缩放比例
> final int minSideLength = Math.min(width, height);
> opts.inSampleSize =
> BitmapUtils.computeSampleSize(opts.outWidth, opts.outHeight, minSideLength,
> width * height);
> opts.inJustDecodeBounds = false;
> opts.inInputShareable = true;
> opts.inPurgeable = true;
> }
>
> try {
> bitmap = BitmapFactory.decodeStream(bis, null, opts);
> } catch (OutOfMemoryError e) {
> e.printStackTrace();
> }
> }
> return bitmap;
> }
>
>
>
>
> --
> 杨辉
> Impossible is nothing!
>
>
>
>
> ------------------------------------------------------------------------------------
> HDExplorer APK (A Nice File Manager,Simplicity but not simple.）
>
> Google Market：
> https://market.android.com/details?id=com.hd.explorer
>
> Google Code：
> http://code.google.com/p/hdexplorer/
>
>
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