What about this?
string PleaseEnter = (EditText)FindViewById(R.id.PleaseEnter).getText();
if(PleaseEnter.equals("1")){
tv.setText(PleaseEnter);
}else if(PleaseEnter.equals("2")){
tv.setText(PleaseEnter);
}
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Ma
Sent: Thursday, February 23, 2012 2:44 PM
To: Android Developers
Subject: [android-developers] If statement help and text displaying on the
screen
I ran my code and in eclipse in the log it is showing under text the output
as what my else statement is set to. I do not see this text on the screen. I
am trying to compare a number to a number in my if statement. I have stated
PleaseEnter as android:inputType="number" in the layout. I have included
some of the ways that I have tried to change my if statement to compare the
values. I need help with 1. Having if statement validated to show what it
needs to and 2. Have the output show on the screen.
try
PleaseEnter=(EditText)findViewById(R.id.PleaseEnter); {
if ("1".equals(PleaseEnter))
//(PleaseEnter.getText().equals("1"))
//(PleaseEnter.equals("1"))
{
// tv.setText("This is the display 1");
System.out.println("This is 1");
}
else if (PleaseEnter.equals("2"))
System.out.println("This 2");
else if (PleaseEnter.equals("3"))
System.out.println("This 3");
else
System.out.println("That number is not recognized.");
}}
catch (Exception ex)
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