On Fri, Jan 9, 2009 at 11:55 AM, [email protected] <[email protected]> wrote: > > Hi, > > I need to send a bitmap to a server. I've written some code, however, > I got stuck on the part where I need to transform my bitmap into byte > []. Here is my code: > > public void updateBitmap(Bitmap bm){ > URL url = null; > HttpURLConnection conn = null; > try { > url = new URL("http://www.myurl.com?";); > } catch (MalformedURLException e) { > e.printStackTrace(); > } > try { > conn = (HttpURLConnection) url.openConnection > (); > } catch (IOException e) { > e.printStackTrace(); > } > try { > conn.setRequestMethod("POST"); > } catch (ProtocolException e) { > e.printStackTrace(); > } > conn.setDoOutput(true); > conn.setDoInput(true); > conn.addRequestProperty("user_id", user.getUsername > ()); > conn.addRequestProperty("pass", user.getPassword()); > conn.addRequestProperty("id", pinId); > > OutputStream os = null; > try { > os = conn.getOutputStream(); > } catch (IOException e) { > e.printStackTrace(); > } > > // Encode bitmap and flush the os
bm.compress(CompressFormat.PNG, 100, os); Note that PNG is lossless and will ignore the 2nd argument. Now, the API *could* have a helper method called save(CompressFormat, Stream) passing the max quality as a default 2nd parameter but that's another story... Cheers, Stoyan --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -~----------~----~----~----~------~----~------~--~---
