I searched Google and found several ways , but I am not sure which is
the correct one.
File mFilePtr = new File(getExternalFilesDir(null), mFilename);
InputStream is = getResources().openRawResource(id);
is.read(mBuffer, 0, bufsize);
The doubt for this is , in the method: openRawResource(id), on the
developers site, it says:
Open a data stream for reading a raw resource. This can only be used
with resources whose value is the name of an asset files -- that is,
it can be used to open drawable, sound, and raw resources; it will
fail on string and color resources.
id The resource identifier to open, as generated by the appt tool.
Is it ok to read my video in that way?
Thanks in advance!
Jiabin
Singapore
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