thanks. But wouldn't that make all items in a vertical layout? What if
I want to have two buttons side-by-side rather than above-and-below?
Also, I have code like this:
showDialog();
// other instructions
I want //other instructions not be carried out until the user has
clicked on a button in the dialog box. Currently //other instructions
are carried out before the user has had a chance to enter text in the
editboxes and click a button. My showDialog() code is:
dl = new Dialog(this);
dl.setTitle("Information Prompt");
dl.setContentView(R.layout.infodlg);
EditText inputBox1 = (EditText)dl.findViewById(R.id.user);
inputBox1.setText("");
EditText inputBox2 = (EditText)dl.findViewById(R.id.pwd);
inputBox2.setText("");
Button bOk = (Button) dl.findViewById(R.id.ok);
bOk.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
EditText inputBox1 =
(EditText)dl.findViewById(R.id.user);
usr = inputBox1.getText().toString();
inputBox1.setText("");
EditText inputBox2 = (EditText)dl.findViewById(R.id.pwd);
pwd = inputBox2.getText().toString();
inputBox2.setText("");
dl.dismiss();
}
});
On Apr 28, 11:30 am, "Dan U." <[EMAIL PROTECTED]> wrote:
> No, you aren't subclassing (extending), but that's not the problem
> with why you don't see the editbox. You are using a horizontal
> LinearLayout. That means the EditText will try to be rendered to the
> right side of the TextView. But, you have set a width of fill_parent
> on the TextView which will push the EditText out of the layout. Either
> change it to wrap_layout or (more appropriate for you) change the
> LinearLayout to vertical.
>
> Now as to subclassingDialog, I think you should still do that instead
> of what you are doing.
>
> On Apr 28, 3:54 am, scimitar <[EMAIL PROTECTED]> wrote:
>
> > isn't that what i'm doing?
>
> > On Apr 28, 6:02 am, Hielko <[EMAIL PROTECTED]> wrote:
>
> > > Do what Dan already suggested: extend thedialogclass.
>
> > > On Apr 28, 11:46 am, scimitar <[EMAIL PROTECTED]> wrote:
>
> > > > Ok. I have the following code:
>
> > > > Dialogdl = newDialog(this);
> > > > dl.setTitle("Information Prompt");
> > > > dl.setContentView(R.layout.infodlg);
> > > > EditText inputBox1 =
> > > > (EditText)dl.findViewById(R.id.user);
> > > > inputBox1.setText("");
> > > > dl.show();
>
> > > > And my infodlg.xml file is:
>
> > > > <?xml version="1.0" encoding="utf-8"?>
> > > > <LinearLayout xmlns:android="http://schemas.android.com/apk/res/
> > > > android"
> > > > android:orientation="horizontal"
> > > > android:layout_width="fill_parent"
> > > > android:layout_height="200px"
>
> > > > <TextView
> > > > android:layout_width="fill_parent"
> > > > android:layout_height="wrap_content"
> > > > android:text="Please Enter your username and password"
> > > > android:textStyle="bold"
> > > > />
> > > > <EditText android:id="@+id/user"
> > > > android:layout_width="fill_parent"
> > > > android:layout_height="wrap_content"
> > > > android:layout_weight="1">
> > > > <requestFocus/>
> > > > </EditText>
> > > > </LinearLayout>
>
> > > > However, thedialogboxshows just the text:"Please Enter your
> > > > username and password", and doesn't show the editbox below it. Why is
> > > > this:
>
> > > > Ideally I would want something like this:
>
> > > > ---------------------------------------------------------------------------------------
> > > > Information Prompt
> > > > ----------------------------------------------------------------------------------------
> > > > Please enter your username and password
> > > > --------------------------------------------------------------------------------------
> > > > username: [\editbox]
> > > > password: [\editbox]
>
> > > > \button["OK"]
> > > > ----------------------------------------------------------------------------------------
>
> > > > Please give me suggestions on how to achieve this.
>
> > > > thanks,
>
> > > > On Apr 27, 9:46 pm, "Dan U." <[EMAIL PROTECTED]> wrote:
>
> > > > > Probably you should look into extending theDialogclass. Just specify
> > > > > your layout and whatever event handling you need in that class, then
> > > > > use it like aDialog. In your case, I'd have some kind of setter
> > > > > method in yourDialogsubclass to set an OnClickListener for whichever
> > > > > buttons you might have in theDialog. That way, you can specify the
> > > > > functionality for a button click outside of yourDialog
> > > > > implementation.
>
> > > > > On Apr 27, 5:52 pm, scimitar <[EMAIL PROTECTED]> wrote:
>
> > > > > > Hi,
>
> > > > > > I want my application to pop up adialogbox that asks for someuser
> > > > > >input. Theuserenters theinputand clicks a button. Based on the
> > > > > > text that theuserhas entered, the application then continues it's
> > > > > > operations. How should I implement this?
>
> > > > > > thanks
>
> > > > On Apr 27, 9:46 pm, "Dan U." <[EMAIL PROTECTED]> wrote:
>
> > > > > Probably you should look into extending theDialogclass. Just specify
> > > > > your layout and whatever event handling you need in that class, then
> > > > > use it like aDialog. In your case, I'd have some kind of setter
> > > > > method in yourDialogsubclass to set an OnClickListener for whichever
> > > > > buttons you might have in theDialog. That way, you can specify the
> > > > > functionality for a button click outside of yourDialog
> > > > > implementation.
>
> > > > > On Apr 27, 5:52 pm, scimitar <[EMAIL PROTECTED]> wrote:
>
> > > > > > Hi,
>
> > > > > > I want my application to pop up adialogbox that asks for someuser
> > > > > >input. Theuserenters theinputand clicks a button. Based on the
> > > > > > text that theuserhas entered, the application then continues it's
> > > > > > operations. How should I implement this?
>
> > > > > > thanks- Hide quoted text -
>
> > > > - Show quoted text -- Hide quoted text -
>
> > > > - Show quoted text -
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